Z^2+(-2-3i)Z-5+i=0

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Solution for Z^2+(-2-3i)Z-5+i=0 equation: 



^2+(-2-3Z)-5+Z=0

We add all the numbers together, and all the variables

(-3Z-2)+Z-5+^2=0

We add all the numbers together, and all the variables

Z+(-3Z-2)=0

We get rid of parentheses

Z-3Z-2=0

We add all the numbers together, and all the variables

-2Z-2=0

We move all terms containing Z to the left, all other terms to the right

-2Z=2

Z=2/-2

Z=-1

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